MySQL DATE函数返回当前日期和加入日期之间的差
首先，找到当前日期，并使用来获得加入日期和当前日期之间的差额DATEDIFF()。
当前日期如下-
mysql> select curdate(); +------------+ | curdate() | +------------+ | 2019-10-26 | +------------+ 1 row in set (0.00 sec)
让我们首先创建一个表-
mysql> create table DemoTable -> ( -> JoiningDate varchar(40) -> );
使用插入命令在表中插入一些记录-
mysql> insert into DemoTable values('10/10/1998');
mysql> insert into DemoTable values('31/12/2010');
mysql> insert into DemoTable values('01/01/2017');
mysql> insert into DemoTable values('25/10/2019');使用select语句显示表中的所有记录-
mysql> select *from DemoTable;
+-------------+ | JoiningDate | +-------------+ | 10/10/1998 | | 31/12/2010 | | 01/01/2017 | | 25/10/2019 | +-------------+ 4 rows in set (0.00 sec)
这是查询以返回当前日期和加入日期之间的差额-
mysql> select datediff(curdate(),str_to_date(JoiningDate,'%d/%m/%Y')) from DemoTable;
这将产生以下输出-
+---------------------------------------------------------+ | datediff(curdate(),str_to_date(JoiningDate,'%d/%m/%Y')) | +---------------------------------------------------------+ | 7686 | | 3221 | | 1028 | | 1 | +---------------------------------------------------------+ 4 rows in set (0.00 sec)