在C ++中获得相同字符串所需的最小旋转
问题陈述
给定一个字符串，我们需要找到获得相同字符串所需的最小转数
示例
如果输入字符串为“bbbbb”，则至少需要旋转一圈
算法
1. Initialize result = 0 2. Make a temporary string equals to original string concatenated with itself. 3. Take the substring of temporary string of size same as original string starting from second character i.e. index 1 4. Increment the counter 5. Check whether the substring becomes equal to original string. If yes, then break the loop. Else go to step 2 and repeat it from the next index
示例
#include <bits/stdc++.h>
using namespace std;
int getRotationCount(string str) {
string temp = str + str;
int n = str.length();
for (int i = 1; i <= n; ++i) {
string sub = temp.substr(i, str.size());
if (str == sub) {
return i;
}
}
return n;
}
int main() {
string str = "bbbbb";
cout << "Rotation count = " << getRotationCount(str) <<
endl;
return 0;
}当您编译并执行上述程序时。它产生以下输出
输出结果
Rotation count = 1
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