好资源导航 » 文章资讯 » 如何按MongoDB中数组内容的差异排序？

如何按MongoDB中数组内容的差异排序？

2024-05-19 01:10:07 391

要按差异排序，请在MongoDB中使用aggregate()。让我们创建一个包含文档的集合-

> db.demo155.insertOne({"Scores":[{"Value":45},{"Value":50}]});
{
   "acknowledged" : true,
   "insertedId" : ObjectId("5e354584fdf09dd6d08539e3")
}
> db.demo155.insertOne({"Scores":[{"Value":60},{"Value":10}]});
{
   "acknowledged" : true,
   "insertedId" : ObjectId("5e35458efdf09dd6d08539e4")
}
> db.demo155.insertOne({"Scores":[{"Value":100},{"Value":95}]});
{
   "acknowledged" : true,
   "insertedId" : ObjectId("5e354599fdf09dd6d08539e5")
}

在find()方法的帮助下显示集合中的所有文档-

> db.demo155.find();

这将产生以下输出-

{ "_id" : ObjectId("5e354584fdf09dd6d08539e3"), "Scores" : [ { "Value" : 45 }, { "Value" : 50 } ] }
{ "_id" : ObjectId("5e35458efdf09dd6d08539e4"), "Scores" : [ { "Value" : 60 }, { "Value" : 10 } ] }
{ "_id" : ObjectId("5e354599fdf09dd6d08539e5"), "Scores" : [ { "Value" : 100 }, { "Value" : 95 } ] }

以下是使用MongoDB按数组内容的差异进行排序的查询-

> db.demo155.aggregate([
...    { "$match": { "Scores.1": { "$exists": true } } },
...    { "$project": {
...       "Scores": "$Scores",
...       "sub": {
...          "$let": {
...             "vars": {
...                "f": { "$arrayElemAt": [ "$Scores", -2 ] },
...                "l": { "$arrayElemAt": [ "$Scores", -1 ] }
...             },
...             "in": { "$subtract": [ "$$l.Value", "$$f.Value" ] }
...          }
...       }
...    }},
...    { "$sort": { "sub": -1 } }
... ])

这将产生以下输出-

{ "_id" : ObjectId("5e354584fdf09dd6d08539e3"), "Scores" : [ { "Value" : 45 }, { "Value" : 50 } ], "sub" : 5 }
{ "_id" : ObjectId("5e354599fdf09dd6d08539e5"), "Scores" : [ { "Value" : 100 }, { "Value" : 95 } ], "sub" : -5 }
{ "_id" : ObjectId("5e35458efdf09dd6d08539e4"), "Scores" : [ { "Value" : 60 }, { "Value" : 10 } ], "sub" : -50 }

返回顶部
3162201930
czq8825@qq.com

如何按MongoDB中数组内容的差异排序？

热门推荐

随机推荐