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MySQL查询排序并显示当前日期与日期之间的差异

2024-05-18 10:03:05 456

为此，请使用ORDERBY子句。当前日期如下-

select now();
+---------------------+
| now()               |
+---------------------+
| 2019-06-09 21:08:16 |
+---------------------+
1 row in set (0.00 sec)

让我们首先创建一个表-

create table DemoTable
   -> (
   -> Id int NOT NULL AUTO_INCREMENT PRIMARY KEY,
   -> DueDate datetime
   -> );

使用插入命令在表中插入一些记录-

insert into DemoTable(DueDate) values('2019-06-12');

insert into DemoTable(DueDate) values('2019-06-01');

insert into DemoTable(DueDate) values('2019-06-05');

insert into DemoTable(DueDate) values('2019-06-10');

insert into DemoTable(DueDate) values('2019-06-11');

使用select语句显示表中的所有记录-

select *from DemoTable;

输出结果

+----+---------------------+
| Id | DueDate             |
+----+---------------------+
| 1  | 2019-06-12 00:00:00 |
| 2  | 2019-06-01 00:00:00 |
| 3  | 2019-06-05 00:00:00 |
| 4  | 2019-06-10 00:00:00 |
| 5  | 2019-06-11 00:00:00 |
+----+---------------------+
5 rows in set (0.00 sec)

这是订购的查询，以获取差额和订购日期。日期之间的差异显示在单独的列中-

select Id,DueDate,DATEDIFF(DueDate, CURDATE()) AS t from DemoTable
   -> order by CASE WHEN t < 0 THEN 1 ELSE 0 END, t;

输出结果

+----+---------------------+------+
| Id | DueDate             | t    |
+----+---------------------+------+
| 4  | 2019-06-10 00:00:00 | 1    |
| 5  | 2019-06-11 00:00:00 | 2    |
| 1  | 2019-06-12 00:00:00 | 3    |
| 2  | 2019-06-01 00:00:00 | -8   |
| 3  | 2019-06-05 00:00:00 | -4   |
+----+---------------------+------+
5 rows in set (0.00 sec)

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MySQL查询排序并显示当前日期与日期之间的差异

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