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LocalDate compareTo()方法

2024-05-18 09:30:06 451

可以使用JavaLocalDate类中的compareTo()方法比较两个LocalDate对象。此方法需要单个参数，即要比较的LocalDate对象。

如果第一个LocalDate对象大于第二个LocalDate对象，则返回正数；如果第一个LocalDate对象小于第二个LocalDate对象，则返回负数；如果两个LocalDate对象相等，则返回零。

演示此的程序如下所示-

示例

import java.time.*;
public class Main {
   public static void main(String[] args) {
      LocalDate ld1 = LocalDate.parse("2019-02-15");
      LocalDate ld2 = LocalDate.parse("2019-02-12");
      System.out.println("The first LocalDate object is: " + ld1);
      System.out.println("The second LocalDate object is: " + ld2);
      int val = ld1.compareTo(ld2);
      if(val > 0)
         System.out.println("\nThe first LocalDate object is greater than the second LocalDate object");
      else if(val < 0)
         System.out.println("\nThe first LocalDate object is lesser than the second LocalDate object");
      else
         System.out.println("\nThe LocalDate objects are equal");
   }
}

输出结果

The first LocalDate object is: 2019-02-15
The second LocalDate object is: 2019-02-12
The first LocalDate object is greater than the second LocalDate object

现在让我们了解上面的程序。

首先，显示两个LocalDate对象。然后使用compareTo()方法对它们进行比较，并使用ifelse语句显示结果。演示这的代码片段如下-

LocalDate ld1 = LocalDate.parse("2019-02-15");
LocalDate ld2 = LocalDate.parse("2019-02-12");
System.out.println("The first LocalDate object is: " + ld1);
System.out.println("The second LocalDate object is: " + ld2);
int val = ld1.compareTo(ld2);
if(val > 0)
   System.out.println("\nThe first LocalDate object is greater than the second LocalDate object");
else if(val < 0)
   System.out.println("\nThe first LocalDate object is lesser than the second LocalDate object");
else
   System.out.println("\nThe LocalDate objects are equal");

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LocalDate compareTo()方法

示例

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