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从MySQL表中选择行并使用IN()显示

2024-05-15 15:19:07 352

让我们首先创建一个表-

mysql> create table DemoTable778 (
   ClientId varchar(100),
   ClientName varchar(100)
);

使用插入命令在表中插入一些记录-

mysql> insert into DemoTable778 values('J-101','John');
mysql> insert into DemoTable778 values('A-102','Adam');
mysql> insert into DemoTable778 values('C-103','Chris');
mysql> insert into DemoTable778 values('D-104','David');
mysql> insert into DemoTable778 values('R-105','Robert');

使用select语句显示表中的所有记录-

mysql> select *from DemoTable778;

这将产生以下输出-

+----------+------------+
| ClientId | ClientName |
+----------+------------+
| J-101    | John       |
| A-102    | Adam       |
| C-103    | Chris      |
| D-104    | David      |
| R-105    | Robert     |
+----------+------------+
5 rows in set (0.00 sec)

从MySQL表中选择行并使用IN()-显示

mysql> select *from DemoTable778 where ClientId IN('J-101','A-102','C-103','D-104','R-105');

这将产生以下输出-

+----------+------------+
| ClientId | ClientName |
+----------+------------+
| J-101    | John       |
| A-102    | Adam       |
| C-103    | Chris      |
| D-104    | David      |
| R-105    | Robert     |
+----------+------------+
5 rows in set (0.00 sec)

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从MySQL表中选择行并使用IN()显示

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