在STL中实现LexicoGraphical_Compare的C ++程序
C++函数std::algorithm::lexicographical_compare()测试一个范围是否在字典上小于另一个范围。字典比较是一种比较，通常用于在字典中按字母顺序对单词进行排序。
声明
模板<classInputIterator1，classInputIterator2>
boollexicographical_compare（InputIterator1first1，InputIterator1last1，InputIterator2first2，InputIterator2last2）;
算法
Begin
result = lexicographical_compare(v1.begin(), v1.end(), v2.begin(), v2.end())
if (result == true)
Print v1 is less than v2
result = lexicographical_compare(v1.begin(), v1.end(), v2.begin(), v2.end())
if (result == false)
Print v1 is not less than v2
End示例
#include <iostream>
#include <vector>
#include <algorithm>
#include <string>
using namespace std;
int main(void) {
//v1和v2的初始化
vector<string> v1 = {"One", "Two", "Three"};
vector<string> v2 = {"one", "two", "three"};
bool result;
result = lexicographical_compare(v1.begin(), v1.end(), v2.begin(), v2.end());
if (result == true)
cout << "v1 is less than v2." << endl;
v1[0] = "two";
result = lexicographical_compare(v1.begin(), v1.end(), v2.begin(), v2.end());
if (result == false)
cout << "v1 is not less than v2." << endl;
return 0;
}输出结果
v1 is less than v2. v1 is not less than v2.