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仅返回使用MySQL DISTINCT出现一定次数的字段？

2024-05-14 02:53:04 359

要返回出现一定次数的字段，语法如下：

select distinct yourColumnName, count(yourColumnName)
from yourTableName
where yourColumnName LIKE 'J%'
group by yourColumnName
having count(*) > 1
order by yourColumnName;

让我们首先创建一个表-

mysql> create table DemoTable1500
   -> (
   -> Name varchar(20)
   -> );

使用插入命令在表中插入一些记录-

Mysql> insert into DemoTable1500 values(‘Adam’);
mysql> insert into DemoTable1500 values('John');
mysql> insert into DemoTable1500 values('Mike');
mysql> insert into DemoTable1500 values('John');
mysql> insert into DemoTable1500 values('Jace');
mysql> insert into DemoTable1500 values('Jace');
mysql> insert into DemoTable1500 values('Jackie');

使用select语句显示表中的所有记录-

mysql> select * from DemoTable1500;

这将产生以下输出-

+--------+
| Name   |
+--------+
| Adam   |
| John   |
| Mike   |
| John   |
| Jace   |
| Jace   |
| Jackie |
+--------+
7 rows in set (0.00 sec)

以下是查询以返回使用MySQLDISTINCT出现一定次数的字段-

mysql> select distinct Name, count(Name)
   -> from DemoTable1500
   -> where Name LIKE 'J%'
   -> group by Name
   -> having count(*) > 1
   -> order by Name;

这将产生以下输出-

+------+-------------+
| Name | count(Name) |
+------+-------------+
| Jace |           2 |
| John |           2 |
+------+-------------+
2 rows in set (0.00 sec)

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仅返回使用MySQL DISTINCT出现一定次数的字段？

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