在C ++中找到相关系数的程序
在本教程中，我们将讨论一个找到相关系数的程序。
为此，我们将提供两个数组。我们的任务是找到表示给定值之间关系强度的相关系数。
示例
#include<bits/stdc++.h>
using namespace std;
//函数返回相关系数
float find_coefficient(int X[], int Y[], int n){
int sum_X = 0, sum_Y = 0, sum_XY = 0;
int squareSum_X = 0, squareSum_Y = 0;
for (int i = 0; i < n; i++){
sum_X = sum_X + X[i];
sum_Y = sum_Y + Y[i];
sum_XY = sum_XY + X[i] * Y[i];
squareSum_X = squareSum_X + X[i] * X[i];
squareSum_Y = squareSum_Y + Y[i] * Y[i];
}
float corr = (float)(n * sum_XY - sum_X * sum_Y) / sqrt((n * squareSum_X - sum_X * sum_X) * (n * squareSum_Y - sum_Y * sum_Y));
return corr;
}
int main(){
int X[] = {15, 18, 21, 24, 27};
int Y[] = {25, 25, 27, 31, 32};
int n = sizeof(X)/sizeof(X[0]);
cout<<find_coefficient(X, Y, n);
return 0;
}输出结果
0.953463