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MySQL查询根据条件按月和年获取结果？

2024-04-27 11:21:03 373

您需要将OR条件与WHERE子句一起使用。让我们首先创建一个表-

mysql> create table DemoTable
   (
   Id int NOT NULL AUTO_INCREMENT PRIMARY KEY,
   MonthNumber int,
   YearNumber int
   );

使用插入命令在表中插入一些记录-

mysql> insert into DemoTable(MonthNumber,YearNumber) values(11,2018);

mysql> insert into DemoTable(MonthNumber,YearNumber) values(3,2019);

mysql> insert into DemoTable(MonthNumber,YearNumber) values(12,2018);

mysql> insert into DemoTable(MonthNumber,YearNumber) values(1,2019);

mysql> insert into DemoTable(MonthNumber,YearNumber) values(12,2019);

mysql> insert into DemoTable(MonthNumber,YearNumber) values(6,2018);

使用select语句显示表中的所有记录-

mysql> select *from DemoTable;

这将产生以下输出-

+----+-------------+------------+
| Id | MonthNumber | YearNumber |
+----+-------------+------------+
| 1  | 11          | 2018       |
| 2  | 3           | 2019       |
| 3  | 12          | 2018       |
| 4  | 1           | 2019       |
| 5  | 12          | 2019       |
| 6  | 6           | 2018       |
+----+-------------+------------+
6 rows in set (0.00 sec)

以下是按月和年获取结果的查询-

mysql> select Id,MonthNumber,YearNumber from DemoTable
where (MonthNumber >= 11 AND YearNumber = 2019)
OR
(MonthNumber <=11 AND YearNumber = 2018);

这将产生以下输出-

+----+-------------+------------+
| Id | MonthNumber | YearNumber |
+----+-------------+------------+
| 1  | 11          | 2018       |
| 5  | 12          | 2019       |
| 6  | 6           | 2018       |
+----+-------------+------------+
3 rows in set (0.00 sec)

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MySQL查询根据条件按月和年获取结果？

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