Java程序打印给定数字的反面
以下是反转给定数字的算法。
算法
1. Get the number to reverse. 2. Hold the number in temporary variable. 3. Start the while loop with condition temp >0. 4. Store the first digit in the temporary variable d by performing modulus operation on temp with 10. 5. Multiply the revnum (initialized with 0) with 10 and concatenate the digit obtained in the previous step. 6. Reduce one digit in the temp by dividing with 10.
示例
import java.util.Scanner;
public class ReverseOfANumber {
public static void main(String args[]) {
int d, number,temp, revnum = 0;
Scanner sc = new Scanner(System.in);
System.out.println("Enter a number ::");
number = sc.nextInt();
temp = number;
while (temp >0) {
d = temp %10;
revnum = (revnum*10)+d;
temp = temp/10;
}
System.out.println("给定数字的反向是："+revnum);
}
}输出结果
Enter a number :: 5112115 给定数字的反向是：5112115
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