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Java中AbstractSequentialList的indexOf()方法

2024-04-25 03:02:03 469

该indexOf()方法从AbstractList类继承。它用于返回此列表中指定元素的首次出现的索引。如果列表为空，则返回-1。

语法如下-

public int indexOf(Object ele)

在这里，ele是您想要为其索引的元素。

要使用Java中的AbstractSequentialList类，您需要导入以下包-

import java.util.AbstractSequentialList;

以下是indexOf()在Java中实现AbstractSequentialList方法的示例-

示例

import java.util.LinkedList;
import java.util.AbstractSequentialList;

public class Demo {
   public static void main(String[] args) {
      AbstractSequentialList<Integer> absSequential = new LinkedList<>();
      absSequential.add(110);
      absSequential.add(320);
      absSequential.add(400);
      absSequential.add(550);
      absSequential.add(600);
      absSequential.add(700);
      absSequential.add(900);
      System.out.println("Elements in the AbstractSequentialList = "+absSequential);
      System.out.println("Elements in the AbstractSequentialList = "+absSequential.indexOf(550));
   }
}

输出结果

Elements in the AbstractSequentialList = [110, 320, 400, 550, 600, 700, 900]
Elements in the AbstractSequentialList = 3

让我们看看另一个不存在元素的示例-

示例

import java.util.LinkedList;
import java.util.AbstractSequentialList;

public class Demo {
   public static void main(String[] args) {
      AbstractSequentialList<Integer> absSequential = new LinkedList<>();
      absSequential.add(110);
      absSequential.add(320);
      absSequential.add(400);
      absSequential.add(550);
      absSequential.add(600);
      absSequential.add(700);
      absSequential.add(900);
      System.out.println("Elements in the AbstractSequentialList = "+absSequential);
      System.out.println("Elements in the AbstractSequentialList = "+absSequential.indexOf(10));
   }
}

输出结果

Elements in the AbstractSequentialList = [110, 320, 400, 550, 600, 700, 900]
Elements in the AbstractSequentialList = -1

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Java中AbstractSequentialList的indexOf()方法

示例

示例

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