在MongoDB中对嵌套对象进行组查询？
为此，在MongoDB中将点符号和$group一起使用。让我们创建一个包含文档的集合-
> db.demo617.insertOne(
... {
...
... "clientDetails": {
... "Name": "Chris",
... "Age":32,
... "Project":"Online Library Management System"
... }
... }
... );
{
"acknowledged" : true,
"insertedId" : ObjectId("5e99d2b86c954c74be91e69b")
}
>
> db.demo617.insertOne(
... {
...
... "clientDetails": {
... "Name": "David",
... "Age":34,
... "Project":"Online Hospital Management System"
... }
... }
... );
{
"acknowledged" : true,
"insertedId" : ObjectId("5e99d2b86c954c74be91e69c")
}
>
> db.demo617.insertOne(
... {
...
... "clientDetails": {
... "Name": "David",
... "Age":34,
... "Project":"Online Library Management System"
... }
... }
... );
{
"acknowledged" : true,
"insertedId" : ObjectId("5e99d2b96c954c74be91e69d")
}在find()方法的帮助下显示集合中的所有文档-
> db.demo617.find();
这将产生以下输出-
{ "_id" : ObjectId("5e99d2b86c954c74be91e69b"), "clientDetails" : { "Name" : "Chris", "Age" : 32, "Project" : "Online Library Management System" } }
{ "_id" : ObjectId("5e99d2b86c954c74be91e69c"), "clientDetails" : { "Name" : "David", "Age" : 34, "Project" : "Online Hospital Management System" } }
{ "_id" : ObjectId("5e99d2b96c954c74be91e69d"), "clientDetails" : { "Name" : "David", "Age" : 34, "Project" : "Online Library Management System" } }组查询MongoDB中的嵌套对象-
> db.demo617.aggregate({ $group : {_id : "$clientDetails.Project", All : { $sum : 1 }} });这将产生以下输出-
{ "_id" : "Online Hosiptal Management System", "All" : 1 }
{ "_id" : "Online Library Management System", "All" : 2 }热门推荐
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