C#中的MathF.Sin()方法与示例
C#中的MathF.Sin()方法用于返回给定浮点值参数的正弦值。
语法
以下是语法-
public static float Sin (float val);
在上方，Val是要返回其正弦的角度。
示例
现在让我们看一个实现MathF.Sin()方法的示例-
using System;
public class Demo {
public static void Main(){
float val1 = 10f;
float val2 = float.NaN;
Console.WriteLine("MathF.Tan(val1) = "+MathF.Tan(val1));
Console.WriteLine("MathF.Tan(val2) = "+MathF.Tan(val2));
}
}输出结果
这将产生以下输出-
MathF.Sign(val1) = -0.5440211 MathF.Sign(val2) = NaN
示例
现在让我们来看另一个实现MathF.Sin()方法的示例-
using System;
public class Demo {
public static void Main(){
float val1 = float.PositiveInfinity;
float val2 = float.NegativeInfinity;
float val3 = (20f * (MathF.PI)) / 180;
Console.WriteLine("MathF.Sin(val1) = "+MathF.Sin(val1));
Console.WriteLine("MathF.Sin(val2) = "+MathF.Sin(val2));
Console.WriteLine("MathF.Sin(val3) = "+MathF.Sin(val3));
}
}输出结果
这将产生以下输出-
MathF.Sin(val1) = NaN MathF.Sin(val2) = NaN MathF.Sin(val3) = 0.3420202
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