Java如何执行HTTP Get请求？
下面是一个使用HttpClient库通过HttpGet请求检索网站内容的示例。我们从创建DefaultHttpClient类的实例开始。然后，我们通过创建HttpGet类的实例来定义Httpget请求，并指定要检索的网站的网址。
要执行请求，我们调用HttpClient.execute()方法并传递HttpGet作为参数。该执行返回一个HttpResponse对象。从该响应对象中，我们可以通过访问getEntity().getContent()来读取网站的内容，这将使我们InputStream对该内容有所了解。
有关更多详细信息，请看下面的代码片段：
package org.nhooo.example.httpclient;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.HttpClientBuilder;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
public class HttpGetExample {
public static void main(String[] args) {
HttpClient client = HttpClientBuilder.create().build();
HttpGet request = new HttpGet("https://kodejava.org");
try {
HttpResponse response = client.execute(request);
HttpEntity entity = response.getEntity();
if (entity != null) {
try (InputStream stream = entity.getContent()) {
BufferedReader reader =
new BufferedReader(new InputStreamReader(stream));
String line;
while ((line = reader.readLine()) != null) {
System.out.println(line);
}
}
}
} catch (IOException e) {
e.printStackTrace();
}
}
}Maven依赖
<!-- https://search.maven.org/remotecontent?filepath=org/apache/httpcomponents/httpclient/4.5.9/httpclient-4.5.9.jar -->
<dependency>
<groupId>org.apache.httpcomponents</groupId>
<artifactId>httpclient</artifactId>
<version>4.5.9</version>
</dependency>