C++计算每个字符出现的次数
本文实例为大家分享了C++计算每个字符出现的次数的实现代码，供大家参考，具体内容如下
#include<iostream>
//#include<cstdlib>
#include<ctime>
usingnamespacestd;
constintNUMBER_OF_LETTERS=26;
constintNUMBER_OF_RANDOM_LETTERS=100;
voidcreateArray(char[]);
voiddisplayArray(constchar[]);
voidcountLetters(constchar[],int[]);
voiddisplayCounts(constint[]);
intmain()
{
charchars[NUMBER_OF_RANDOM_LETTERS];
createArray(chars);
cout<<"Thelowercaselettersare:"<<endl;
displayArray(chars);
intcounts[NUMBER_OF_LETTERS];
countLetters(chars,counts);
cout<<"\nTheoccurrencesofeachletterare:"<<endl;
displayCounts(counts);
return0;
}
voidcreateArray(charchars[])
{
srand((unsignedint)time(0));
for(inti=0;i<NUMBER_OF_RANDOM_LETTERS;i++)
{
chars[i]=static_cast<char>('a'+rand()%('z'-'a'+1));
}
}
voiddisplayArray(constcharchars[])
{
for(inti=0;i<NUMBER_OF_RANDOM_LETTERS;i++)
{
if((i+1)%20==0)
cout<<chars[i]<<""<<endl;
else
cout<<chars[i]<<"";
}
}
voidcountLetters(constcharchars[],intcounts[])
{
for(inti=0;i<NUMBER_OF_LETTERS;i++)
counts[i]=0;
for(inti=0;i<NUMBER_OF_RANDOM_LETTERS;i++)
counts[chars[i]-'a']++;//经典
}
voiddisplayCounts(constintcounts[])
{
for(inti=0;i<NUMBER_OF_LETTERS;i++)
{
if((i+1)%10==0)
cout<<counts[i]<<""<<static_cast<char>(i+'a')<<endl;
else
cout<<counts[i]<<""<<static_cast<char>(i+'a')<<"";
}
cout<<endl;
}
以上就是本文的全部内容，希望对大家的学习有所帮助。