python消除序列的重复值并保持顺序不变的实例
python消除序列的重复值，并保持原来顺序
1、如果仅仅消除重复元素，可以简单的构造一个集合
$python
Python3.5.2(default,Nov232017,16:37:01)
[GCC5.4.020160609]onlinux
Type"help","copyright","credits"or"license"formoreinformation.
>>>a=[1,3,5,1,8,1,5]
>>>set(a)
{8,1,3,5}
>>>
2、利用集合或者生成器解决：值必须是hashable类型
$python Python3.5.2(default,Nov232017,16:37:01) [GCC5.4.020160609]onlinux Type"help","copyright","credits"or"license"formoreinformation. >>>defdupe(items): ...seen=set() ...foriteminitems: ...ifitemnotinseen: ...yielditem ...seen.add(item) ... >>>a=[1,3,5,1,8,1,5] >>>list(dupe(a)) [1,3,5,8] >>>
3、消除元素不可哈希：如字典类型
Python3.5.2(default,Nov232017,16:37:01)
[GCC5.4.020160609]onlinux
Type"help","copyright","credits"or"license"formoreinformation.
>>>defrem(items,key=None):
...seen=set()
...foriteminitems:
...va=itemifkeyisNoneelsekey(item)
...ifvanotinseen:
...yielditem
...seen.add(va)
...
>>>a=[{'x':1,'y':2},{'x':1,'y':3},{'x':1,'y':2},{'x':2,'y':4}]>>>list(rem(a,key=lambdad:(d['x'],d['y'])))
[{'y':2,'x':1},{'y':3,'x':1},{'y':4,'x':2}]
>>>list(rem(a,key=lambdad:d['x']))
[{'y':2,'x':1},{'y':4,'x':2}]
>>>>>>#lambdaisananonymousfunction:
...fuc=lambda:'haha'
>>>print(f())
>>>print(fuc())
haha
>>>
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