C 程序以查找给定数字的二进制补码!
可以用两种方法计算给定二进制数的二进制补码，如下所示-
方法1-将给定的二进制数转换为补码，然后加1。
方法2-从最低有效位(LSB)设置的第一位之后的尾随零，包括保持不变和其余全部应补码。
为给定的二进制数找到二进制补码的逻辑如下-
for(i = SIZE - 1; i >= 0; i--){
if(one[i] == '1' && carry == 1){
two[i] = '0';
}
else if(one[i] == '0' && carry == 1){
two[i] = '1';
carry = 0;
} else {
two[i] = one[i];
}
}
two[SIZE] = '\0';
printf("Two's complement of binary number %s is %s\n",num, two);从给定的二进制数中找到一个补码的逻辑是-
for(i = 0; i < SIZE; i++){
if(num[i] == '0'){
one[i] = '1';
}
else if(num[i] == '1'){
one[i] = '0';
}
}
one[SIZE] = '\0';
printf("Ones' complement of binary number %s is %s\n",num, one);示例
以下是用于查找给定数字的二进制补码的C程序-
#include输出结果#include #define SIZE 8 int main(){ int i, carry = 1; char num[SIZE + 1], one[SIZE + 1], two[SIZE + 1]; printf("Enter the binary number\n"); gets(num); for(i = 0; i < SIZE; i++){ if(num[i] == '0'){ one[i] = '1'; } else if(num[i] == '1'){ one[i] = '0'; } } one[SIZE] = '\0'; printf("Ones' complement of binary number %s is %s\n",num, one); for(i = SIZE - 1; i >= 0; i--){ if(one[i] == '1' && carry == 1){ two[i] = '0'; } else if(one[i] == '0' && carry == 1){ two[i] = '1'; carry = 0; } else{ two[i] = one[i]; } } two[SIZE] = '\0'; printf("Two's complement of binary number %s is %s\n",num, two); return 0; }
执行上述程序时，会产生以下结果-
Enter the binary number 1000010 Ones' complement of binary number 1000010 is 0111101 Two's complement of binary number 1000010 is 0111110
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