数组（C ++）中偶数和奇数索引元素的绝对差？
在这里，我们将看到如何获取数组中奇数和偶数索引元素的绝对差。绝对差表示如果一对差为负，则取绝对值。例如，让数字为{1、2、3、4、5、6、7、8、9}。因此，偶数位置元素为1、3、5、7、9（从0开始），奇数位置元素为2、4、6、8。因此，偶数位置数据的差为|1-3|。=2，然后|2-5|=3，|3-7|=4和|4-9|=5同样，位数的奇数差将为4。
算法
offEvenDiff(arr,n)
begin
even := 0
odd := 0
for i := 0 to n-1, do
if i is even, then
even := |even – arr[i]|
else
odd := |odd – arr[i]|
done
return (odd,even)
end示例
#include<iostream>
#include<cmath>
using namespace std;
void oddEvenDiff(int arr[], int n, int &o, int &e) {
int even = 0;
int odd = 0;
for (int i = 0; i < n; i++) {
if (i % 2 == 0) {
even = abs(even - arr[i]); //get the even difference
} else {
odd = abs(odd - arr[i]);
}
}
e = even;
o = odd;
}
main() {
int arr[] = {1, 2, 3, 4, 5, 6, 7, 8, 9};
int n = sizeof(arr) / sizeof(arr[0]);
int odd, even;
oddEvenDiff(arr, n, odd, even);
cout << "The odd and even differences are: " << odd << " and " << even;
}输出结果
The odd and even differences are: 4 and 5