在C ++中将介于1到3999之间的十进制数转换为罗马数字
在本教程中，我们将讨论将1到3999之间的十进制数字转换为罗马数字的程序。
为此，我们将提供一个随机整数。我们的任务是将给定数字转换为其等效的罗马数字。
示例
#include <bits/stdc++.h>
using namespace std;
//将十进制转换为罗马数字
int printRoman(int number){
int num[] = {1,4,5,9,10,40,50,90,100,400,500,900,1000};
string sym[] =
{"I","IV","V","IX","X","XL","L","XC","C","CD","D","CM","M"};
int i=12;
while(number>0){
int div = number/num[i];
number = number%num[i];
while(div--){
cout<<sym[i];
}
i--;
}
}
int main(){
int number = 3949;
printRoman(number);
return 0;
}输出结果
MMMCMXLIX