如何使用Java RegEx匹配非单词边界?
您可以使用元字符“\\B”来匹配非单词边界。
例子1
import java.util.Scanner; import java.util.regex.Matcher; import java.util.regex.Pattern; public class Example { public static void main(String args[]) { //从用户读取字符串 System.out.println("Enter a String"); Scanner sc = new Scanner(System.in); String input = sc.nextLine(); String regex = "\\B"; //编译正则表达式 Pattern pattern = Pattern.compile(regex); //检索匹配器对象 Matcher matcher = pattern.matcher(input); int count = 0; while(matcher.find()) { count++; } System.out.println("Number of non-word boundaries: "+count); } }
输出结果
Enter a String this is a sample text Number of non-word boundaries: 12
例子2
import java.util.Scanner; import java.util.regex.Matcher; import java.util.regex.Pattern; public class Example { public static void main( String args[] ) { String regex = "\\Bin"; Scanner sc = new Scanner(System.in); System.out.println("Enter a string: "); String input = sc.nextLine(); Pattern p = Pattern.compile(regex); Matcher m = p.matcher(input); int count = 0; while(m.find()) { count++; } System.out.println("no of non-word boundaries: "+count); } }
输出结果
Enter a string: this is a sample text in win tin pin sin no of non-word boundaries: 4