使用MongoDB聚合计算NAME字段中重复名称的频率？
要计算频率，请在中与$group分组aggregate()。让我们创建一个包含文档的集合-
> db.demo635.insertOne({Name:"Chris"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e9c10f06c954c74be91e6cc")
}
> db.demo635.insertOne({Name:"David"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e9c10f46c954c74be91e6cd")
}
> db.demo635.insertOne({Name:"David"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e9c10f66c954c74be91e6ce")
}
> db.demo635.insertOne({Name:"Chris"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e9c10f86c954c74be91e6cf")
}
> db.demo635.insertOne({Name:"Bob"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e9c10fb6c954c74be91e6d0")
}
> db.demo635.insertOne({Name:"Chris"});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e9c10fc6c954c74be91e6d1")
}在find()方法的帮助下显示集合中的所有文档-
> db.demo635.find();
这将产生以下输出-
{ "_id" : ObjectId("5e9c10f06c954c74be91e6cc"), "Name" : "Chris" }
{ "_id" : ObjectId("5e9c10f46c954c74be91e6cd"), "Name" : "David" }
{ "_id" : ObjectId("5e9c10f66c954c74be91e6ce"), "Name" : "David" }
{ "_id" : ObjectId("5e9c10f86c954c74be91e6cf"), "Name" : "Chris" }
{ "_id" : ObjectId("5e9c10fb6c954c74be91e6d0"), "Name" : "Bob" }
{ "_id" : ObjectId("5e9c10fc6c954c74be91e6d1"), "Name" : "Chris" }以下是使用MongoDB聚合框架计算频率的查询-
> db.demo635.aggregate([
... { $unwind: "$Name" },
... { $group: { "_id": "$Name", TotalFrequency: { $sum : 1 } } }
... ]
... );这将产生以下输出-
{ "_id" : "David", "TotalFrequency" : 2 }
{ "_id" : "Bob", "TotalFrequency" : 1 }
{ "_id" : "Chris", "TotalFrequency" : 3 }