如何编写MySQL查询以选择前10条记录？
要选择前10条记录，我们可以先按升序或降序对记录进行排序。这样，使用LIMIT10只能获取10条记录-
select *from (select *from yourTableName ORDER BY yourColumnName ASC LIMIT 10)anyAliasName ORDER BY yourColumnName DESC;
让我们首先创建一个表-
mysql> create table DemoTable683(Page int);
使用插入命令在表中插入一些记录-
mysql> insert into DemoTable683 values(100); mysql> insert into DemoTable683 values(101); mysql> insert into DemoTable683 values(102); mysql> insert into DemoTable683 values(103); mysql> insert into DemoTable683 values(104); mysql> insert into DemoTable683 values(105); mysql> insert into DemoTable683 values(106); mysql> insert into DemoTable683 values(107); mysql> insert into DemoTable683 values(108); mysql> insert into DemoTable683 values(109); mysql> insert into DemoTable683 values(110); mysql> insert into DemoTable683 values(111); mysql> insert into DemoTable683 values(112); mysql> insert into DemoTable683 values(113); mysql> insert into DemoTable683 values(114);
使用select语句显示表中的所有记录-
mysql> select *from DemoTable683;
这将产生以下输出-
+------+ | Page | +------+ | 100 | | 101 | | 102 | | 103 | | 104 | | 105 | | 106 | | 107 | | 108 | | 109 | | 110 | | 111 | | 112 | | 113 | | 114 | +------+ 15 rows in set (0.00 sec)
以下是查询以选择MySQL中的前10条记录-
mysql> select *from (select *from DemoTable683 ORDER BY Page ASC LIMIT 10)tbl ORDER BY Page DESC;
这将产生以下输出-
+------+ | Page | +------+ | 109 | | 108 | | 107 | | 106 | | 105 | | 104 | | 103 | | 102 | | 101 | | 100 | +------+ 10 rows in set (0.00 sec)