查找平均值并显示重复ID的最大平均值？
为此，请使用AVG()。要找到最大平均值，请使用MAX()并按ID分组。让我们首先创建一个表-
mysql> create table DemoTable -> ( -> PlayerId int, -> PlayerScore int -> );
使用插入命令在表中插入一些记录-
mysql> insert into DemoTable values(1,78); mysql> insert into DemoTable values(2,82); mysql> insert into DemoTable values(1,45); mysql> insert into DemoTable values(3,97); mysql> insert into DemoTable values(2,79);
使用select语句显示表中的所有记录-
mysql> select *from DemoTable;
这将产生以下输出-
+----------+-------------+ | PlayerId | PlayerScore | +----------+-------------+ | 1 | 78 | | 2 | 82 | | 1 | 45 | | 3 | 97 | | 2 | 79 | +----------+-------------+ 5 rows in set (0.00 sec)
这是查询以查找MySQL中重复ID的最大平均值-
mysql> select PlayerId from DemoTable -> group by PlayerId -> having avg(PlayerScore) > 80;
这将产生以下输出-
+----------+ | PlayerId | +----------+ | 2 | | 3 | +----------+ 2 rows in set (0.00 sec)