我们可以从Java的静态块中抛出Unchecked Exception吗？
甲静块是代码使用静态关键字的块。通常，这些用于初始化静态成员。JVM在类加载时在main方法之前执行静态块。
示例
public class MyClass {
static{
System.out.println("Hello this is a static block");
}
public static void main(String args[]){
System.out.println("This is main method");
}
}输出结果
Hello this is a static block This is main method
静态块中的异常
就像Java中的其他任何方法一样，当静态块中发生异常时，您也可以使用try-catch对来处理它。
示例
import java.io.File;
import java.util.Scanner;
public class ThrowingExceptions{
static String path = "D://sample.txt";
static {
try {
Scanner sc = new Scanner(new File(path));
StringBuffer sb = new StringBuffer();
sb.append(sc.nextLine());
String data = sb.toString();
System.out.println(data);
} catch(Exception ex) {
System.out.println("");
}
}
public static void main(String args[]) {
}
}输出结果
This is a sample fileThis is main method
在静态块中抛出异常
每当抛出检查异常时，都需要在当前方法中对其进行处理，或者可以将其抛出（推迟）到调用方法中。
You cannot use throws keyword with a static block, and more over a static block is invoked at compile time (at the time of class loading) no method invokes it.
因此，如果在静态块中使用throw关键字引发异常，则必须将其包装在try-catch块中，否则会生成编译时错误。
示例
import java.io.FileNotFoundException;
public class ThrowingExceptions{
static String path = "D://sample.txt";
static {
FileNotFoundException ex = new FileNotFoundException();
throw ex;
}
public static void main(String args[]) {
}
}编译时错误
ThrowingExceptions.java:4: error: initializer must be able to complete normally
static {
^
ThrowingExceptions.java:6: error: unreported exception FileNotFoundException; must be caught or declared to be thrown
throw ex;
^
2 errors