从C#中的ListDictionary中删除具有指定键的条目
要从ListDictionary中删除具有指定键的条目，代码如下-
示例
using System;
using System.Collections;
using System.Collections.Specialized;
public class Demo {
public static void Main(){
ListDictionary dict1 = new ListDictionary();
dict1.Add("A", "Books");
dict1.Add("B", "Electronics");
dict1.Add("C", "Smart Wearables");
dict1.Add("D", "Pet Supplies");
dict1.Add("E", "Clothing");
dict1.Add("F", "Footwear");
Console.WriteLine("ListDictionary1 elements...");
foreach(DictionaryEntry d in dict1) {
Console.WriteLine(d.Key + " " + d.Value);
}
ListDictionary dict2 = new ListDictionary();
dict2.Add("1", "One");
dict2.Add("2", "Two");
dict2.Add("3", "Three");
dict2.Add("4", "Four");
dict2.Add("5", "Five");
dict2.Add("6", "Six");
Console.WriteLine("\nListDictionary2 elements...");
foreach(DictionaryEntry d in dict2) {
Console.WriteLine(d.Key + " " + d.Value);
}
Console.WriteLine("Count of key/value pairs in Dictionary 2 = "+dict2.Count);
dict2.Remove("4");
Console.WriteLine("Count of key/value pairs in Dictionary 2 (Updated) = "+dict2.Count);
}
}输出结果
这将产生以下输出-
ListDictionary1 elements... A Books B Electronics C Smart Wearables D Pet Supplies E Clothing F Footwear ListDictionary2 elements... 1 One 2 Two 3 Three 4 Four 5 Five 6 Six Count of key/value pairs in Dictionary 2 = 6 Count of key/value pairs in Dictionary 2 (Updated) = 5
示例
让我们看另一个例子-
using System;
using System.Collections;
using System.Collections.Specialized;
public class Demo {
public static void Main() {
ListDictionary dict = new ListDictionary();
dict.Add("1", "One");
dict.Add("2", "Two");
dict.Add("3", "Three");
dict.Add("4", "Four");
dict.Add("5", "Five");
dict.Add("6", "Six");
Console.WriteLine("ListDictionary elements...");
foreach(DictionaryEntry d in dict) {
Console.WriteLine(d.Key + " " + d.Value);
}
Console.WriteLine("Count of key/value pairs in Dictionary = "+dict.Count);
dict.Remove("2");
dict.Remove("3");
dict.Remove("4");
Console.WriteLine("Count of key/value pairs in Dictionary (Updated) = "+dict.Count);
}
}输出结果
这将产生以下输出-
ListDictionary elements... 1 One 2 Two 3 Three 4 Four 5 Five 6 Six Count of key/value pairs in Dictionary = 6 Count of key/value pairs in Dictionary (Updated) = 3