C#程序在列表中找到最大，最小，第二大，第二小
设定列表
var val = new int[] {
99,
35,
26,
87
};现在获得最大数量。
val.Max(z => z);
最小人数
val.Min(z => z);
第二大数字
val.OrderByDescending(z => z).Skip(1).First();
第二小数
val.OrderBy(z => z).Skip(1).First();
以下是代码-
示例
using System;
using System.Linq;
public class Program {
public static void Main() {
var val = new int[] {
99,
35,
26,
87
};
var maxNum = val.Max(z => z);
Console.WriteLine("Maximum Number: " + maxNum);
var minNum = val.Min(z => z);
Console.WriteLine("Minimum Number: " + minNum);
var secondMax = val.OrderByDescending(z => z).Skip(1).First();
Console.WriteLine("Second Largest Number: " + secondMax);
var secondMin = val.OrderBy(z => z).Skip(1).First();
Console.WriteLine("Second Smallest Number: " + secondMin);
}
}输出结果
Maximum Number: 99 Minimum Number: 26 Second Largest Number: 87 Second Smallest Number: 35