如何在MySQL的一周中的特定日期选择行？
对于星期几，请使用DAYOFWEEK()。
让我们首先创建一个表-
mysql> create table DemoTable785 ( CustomerId int NOT NULL AUTO_INCREMENT PRIMARY KEY, CustomerName varchar(100), ShoppingDate date );
使用插入命令在表中插入一些记录-
mysql> insert into DemoTable785(CustomerName,ShoppingDate) values('Chris','2019-07-03');
mysql> insert into DemoTable785(CustomerName,ShoppingDate) values('Robert','2019-07-01');
mysql> insert into DemoTable785(CustomerName,ShoppingDate) values('David','2019-07-06');
mysql> insert into DemoTable785(CustomerName,ShoppingDate) values('Carol','2019-07-19');使用select语句显示表中的所有记录-
mysql> select *from DemoTable785;
这将产生以下输出-
+------------+--------------+--------------+ | CustomerId | CustomerName | ShoppingDate | +------------+--------------+--------------+ | 1 | Chris | 2019-07-03 | | 2 | Robert | 2019-07-01 | | 3 | David | 2019-07-06 | | 4 | Carol | 2019-07-19 | +------------+--------------+--------------+ 4 rows in set (0.00 sec)
以下是查询以选择属于一周中特定日期的行-
mysql> select *from DemoTable785 where DAYOFWEEK(ShoppingDate)=2;
这将产生以下输出-
+------------+--------------+--------------+ | CustomerId | CustomerName | ShoppingDate | +------------+--------------+--------------+ | 2 | Robert | 2019-07-01 | +------------+--------------+--------------+ 1 row in set (0.00 sec)