实现并行数组的C ++程序
并行数组是包含多个数组的结构。这些数组中的每个数组都具有相同的大小，并且数组元素彼此相关。并行数组中的所有元素都代表一个公共实体。
并行数组的示例如下-
employee_name = { Harry, Sally, Mark, Frank, Judy }
employee_salary = {10000, 5000, 20000, 12000, 5000}在上面的示例中，5个不同雇员的姓名和薪水存储在2个数组中。
演示并行数组的程序如下：
示例
#include <iostream>
#include <string>
using namespace std;
int main() {
int max = 0, index = 0;
string empName [ ] = {"Harry", "Sally", "Mark", "Frank", "Judy" };
string empDept [ ] = {"IT", "Sales", "IT", "HR", "Sales"};
int empSal[ ] = {10000, 5000, 20000, 12000, 5000 };
int n = sizeof(empSal)/sizeof(empSal[0]);
for(int i = 0; i < n; i++) {
if (empSal[i] > max) {
max = empSal[i];
index = i;
}
}
cout << "The highest salary is "<< max <<" and is earned by
"<<empName[index]<<" belonging to "<<empDept[index]<<" department";
return 0;
}输出结果
上面程序的输出如下-
The highest salary is 20000 and is earned by Mark belonging to IT department
在上面的程序中，声明了三个数组，分别包含员工姓名，部门和薪水。这在下面给出-
string empName [ ] = {"Harry", "Sally", "Mark", "Frank", "Judy" };
string empDept [ ] = {"IT", "Sales", "IT", "HR", "Sales"};
int empSal[ ] = {10000, 5000, 20000, 12000, 5000 };使用for循环找到最高薪水，并将其存储在max。中。包含最高薪水的索引存储在索引中。这如下所示-
int n = sizeof(empSal)/sizeof(empSal[0]);
for(int i = 0; i < n; i++) {
if (empSal[i] > max) {
max = empSal[i];
index = i;
}
}最后，显示最高薪水及其相应的员工姓名和部门。这在下面给出-
cout << "The highest salary is "<< max <<" and is earned by "<<empName[index]<<" belonging to "<<empDept[index]<<" department";