通过MySQL SELECT从MySQL的另一个表插入表中的值？
为此，请使用INSERTINTOSELECT语句。让我们首先创建一个表-
mysql> create table DemoTable1 -> ( -> Id int, -> Name varchar(20), -> Age int -> );
使用插入命令在表中插入一些记录-
mysql> insert into DemoTable1 values(100,'Chris',24); mysql> insert into DemoTable1 values(101,'Adam',23); mysql> insert into DemoTable1 values(102,'John',25); mysql> insert into DemoTable1 values(103,'Carol',26);
使用select语句显示表中的所有记录-
mysql> select * from DemoTable1;
这将产生以下输出-
+------+-------+------+ | Id | Name | Age | +------+-------+------+ | 100 | Chris | 24 | | 101 | Adam | 23 | | 102 | John | 25 | | 103 | Carol | 26 | +------+-------+------+ 4 rows in set (0.00 sec)
这是创建第二个表的查询-
mysql> create table DemoTable2 -> ( -> EmployeeId int, -> EmployeeFirstName varchar(20), -> EmployeeAge int -> );
这是在MySQL的DemoTable2中插入值的查询，请从DemoTable1选择-
mysql> insert into DemoTable2(EmployeeId,EmployeeFirstName,EmployeeAge) select Id,Name,Age from DemoTable1 where Id=101; Records: 1 Duplicates: 0 Warnings: 0
让我们检查表记录-
mysql> select * from DemoTable2;
这是创建第二个表的查询-
+------------+-------------------+-------------+ | EmployeeId | EmployeeFirstName | EmployeeAge | +------------+-------------------+-------------+ | 101 | Adam | 23 | +------------+-------------------+-------------+ 1 row in set (0.00 sec)