在MySQL中先按字母顺序排列，然后按数字顺序排列？
您需要将正则表达式与ORDERBY子句一起使用。语法如下：
SELECT *FROM yourTableName ORDER BY IF(yourColumnName RLIKE '^[a-z]', 1, 2),yourColumnName;
为了理解上述语法，让我们创建一个表。创建表的查询如下：
mysql> create table AlphabetFirstThenNumberDemo -> ( -> Id int NOT NULL AUTO_INCREMENT, -> Name varchar(20), -> PRIMARY KEY(Id) -> );
使用insert命令在表中插入一些记录。查询如下：
mysql> insert into AlphabetFirstThenNumberDemo(Name) values('John');
mysql> insert into AlphabetFirstThenNumberDemo(Name) values('Bob');
mysql> insert into AlphabetFirstThenNumberDemo(Name) values('1Sam');
mysql> insert into AlphabetFirstThenNumberDemo(Name) values('Carol');
mysql> insert into AlphabetFirstThenNumberDemo(Name) values('2Larry');
mysql> insert into AlphabetFirstThenNumberDemo(Name) values('David');
mysql> insert into AlphabetFirstThenNumberDemo(Name) values('3Mike');
mysql> insert into AlphabetFirstThenNumberDemo(Name) values('Robert');现在，您可以使用select语句显示表中的所有记录。查询如下：
mysql> select *from AlphabetFirstThenNumberDemo;
以下是输出：
+----+--------+ | Id | Name | +----+--------+ | 1 | John | | 2 | Bob | | 3 | 1Sam | | 4 | Carol | | 5 | 2Larry | | 6 | David | | 7 | 3Mike | | 8 | Robert | +----+--------+ 8 rows in set (0.00 sec)
这是查询顺序，首先是字母，然后是数字。查询如下：
mysql> select *from AlphabetFirstThenNumberDemo -> ORDER BY IF(Name RLIKE '^[a-z]', 1, 2),Name;
以下是输出：
+----+--------+ | Id | Name | +----+--------+ | 2 | Bob | | 4 | Carol | | 6 | David | | 1 | John | | 8 | Robert | | 3 | 1Sam | | 5 | 2Larry | | 7 | 3Mike | +----+--------+ 8 rows in set (0.00 sec)