MySQL查询以获取当前日期记录,其中一列显示当前日期
为了实现这一点,下面是我们使用DATE(NOW())的语法-
select *from yourTableName where DATE(yourColumnName)=DATE(NOW());
让我们首先创建一个表-
mysql> create table DemoTable706 ( UserId varchar(100), UserName varchar(100), UserSignupDate datetime );
使用插入命令在表中插入一些记录-
mysql> insert into DemoTable706 values('John1@gmail.com','John','2019-01-31 12:45:22'); mysql> insert into DemoTable706 values('Chris123@gmail.com','Chris','2019-07-22 10:05:02'); mysql> insert into DemoTable706 values('12Robert@gmail.com','Robert','2019-06-22 11:25:22'); mysql> insert into DemoTable706 values('DavidM@gmail.com','David','2019-07-22 00:00:02');
使用select语句显示表中的所有记录-
mysql> select *from DemoTable706;
这将产生以下输出-
+--------------------+----------+---------------------+ | UserId | UserName | UserSignupDate | +--------------------+----------+---------------------+ | John1@gmail.com | John | 2019-01-31 12:45:22 | | Chris123@gmail.com | Chris | 2019-07-22 10:05:02 | | 12Robert@gmail.com | Robert | 2019-06-22 11:25:22 | | DavidM@gmail.com | David | 2019-07-22 00:00:02 | +--------------------+----------+---------------------+ 4 rows in set (0.00 sec)
以下是获取记录的查询,其中一列显示当前日期-
mysql> select *from DemoTable706 where DATE(UserSignupDate)=DATE(NOW());
这将产生以下输出-
+--------------------+----------+---------------------+ | UserId | UserName | UserSignupDate | +--------------------+----------+---------------------+ | Chris123@gmail.com | Chris | 2019-07-22 10:05:02 | | DavidM@gmail.com | David | 2019-07-22 00:00:02 | +--------------------+----------+---------------------+ 2 rows in set (0.00 sec)