C#Convert.ToInt32(double)方法-将double值转换为int
C＃Convert.ToInt32(double)方法
Convert.ToInt32(double)方法用于将特定的double值（双精度浮点数）转换为其等效的整数（int32字节带符号数字）。
语法：
int Convert.ToInt32(double value);
它接受双精度值/变量作为参数，并返回其等效的带符号整数。
示例
Input:
double a = 1023.12;
Output:
1023
Input:
double a = 1023.56;
Output:
1024码：
using System;
using System.Text;
namespace ConsoleApplication3
{
class Program
{
static void Main(string[] args)
{
double a = 1023.00;
double b = 1023.56;
double c = 1023.12;
Console.WriteLine("value of a: {0}, type of a: {1}", a, a.GetType());
Console.WriteLine("value of b: {0}, type of b: {1}", b, b.GetType());
Console.WriteLine("value of c: {0}, type of c: {1}", c, c.GetType());
//converting to Int32 & printing values & types
Console.WriteLine("value: {0}, type: {1}", Convert.ToInt32(a), Convert.ToInt32(a).GetType());
Console.WriteLine("value: {0}, type: {1}", Convert.ToInt32(b), Convert.ToInt32(b).GetType());
Console.WriteLine("value: {0}, type: {1}", Convert.ToInt32(c), Convert.ToInt32(c).GetType());
//按ENTER退出
Console.ReadLine();
}
}
}输出结果
value of a: 1023, type of a: System.Double value of b: 1023.56, type of b: System.Double value of c: 1023.12, type of c: System.Double value: 1023, type: System.Int32 value: 1024, type: System.Int32 value: 1023, type: System.Int32