Java中如何使用RuleBasedCollator类对字符串数据数组进行排序？
我们可以使用java.text.Collator该类以特定于语言的顺序对字符串进行排序。使用java.text.Collator该类可使字符串不仅按其字符的ASCII码排序，而且将遵循字符的语言自然顺序。
如果预定义的排序规则不符合您的需求，则可以设计自己的规则并将其分配给RuleBasedCollator对象。自定义的排序规则包含在String传递给RuleBasedCollator构造函数的对象中。
package org.nhooo.example.text;
import java.text.ParseException;
import java.text.RuleBasedCollator;
import java.util.Arrays;
import java.util.Collections;
public class RuleBasedCollatorDemo {
public static void main(String[] args) {
String rule1 = ("< a < b < c");
String rule2 = ("< c < b < a");
String rule3 = ("< c < a < b");
String words[] = {"apple", "banana", "carrot", "apricot", "blueberry", "cabbage"};
try {
RuleBasedCollator rb1 = new RuleBasedCollator(rule1);
RuleBasedCollator rb2 = new RuleBasedCollator(rule2);
RuleBasedCollator rb3 = new RuleBasedCollator(rule3);
System.out.println("original: ");
System.out.println(Arrays.toString(words));
// 根据Rule1排序
Collections.sort(Arrays.asList(words), rb1);
System.out.println("rule: " + rb1.getRules());
System.out.println(Arrays.toString(words));
// 根据Rule2排序
Collections.sort(Arrays.asList(words), rb2);
System.out.println("rule: " + rb2.getRules());
System.out.println(Arrays.toString(words));
// 根据Rule3排序
Collections.sort(Arrays.asList(words), rb3);
System.out.println("rule: " + rb3.getRules());
System.out.println(Arrays.toString(words));
} catch (ParseException e) {
e.printStackTrace();
}
}
}下面是使用不同RuleBasedCollator对字符串进行排序的结果
original: [apple, banana, carrot, apricot, blueberry, cabbage] rule: < a < b < c [apple, apricot, banana, blueberry, cabbage, carrot] rule: < c < b < a [cabbage, carrot, banana, blueberry, apple, apricot] rule: < c < a < b [cabbage, carrot, apple, apricot, banana, blueberry]