正则表达式的字符串替换方法
我有以下几行:
d:\Projects\qqq\Development\qqq.MySol1.sln
d:\Projects\qqq\qqqDevelopment\qqqMySol2.sln
d:\Projects\qqq\Development\MyInstaller.sln
d:\Projects\qqq\qqq\Development\MyInstaller.sln
d:\Projects\Development\MyInstaller.sln
我需要一个正则表达式,这将导致捕获:
Line1:DevelopmentandMySol1.sln
Line2:DevelopmentandMySol2.sln
Line3:DevelopmentandMyInstaller.sln
Line4:DevelopmentandMyInstaller.sln
Line5:DevelopmentandMyInstaller.sln
因此,一个正则表达式,将删除(忽略)字qqq从行。我一直在试图与调节,并有部分的解决方案:
.*\\(?<A>.*)\\.{3}(?<B>.*)
这导致:
Line1:Developmentand.MySol1.sln
Line2:qqqDevelopmentandMySol2.sln
Line3:Developmentandnstaller.sln
Line4:Developmentandnstaller.sln
Line5:Developmentandnstaller.sln
因此,.{3}应固定
1.我认为,应该工作:
.*\\(?:qqq)?(?<A>.*)\\(?:qqq)?(?<B>.*)