如何用C语言编写一个简单的计算器程序？
首先编写C代码以创建一个简单的计算器。然后，按照下面给出的算法编写一个C程序。
算法
Step 1: Declare variables
Step 2: Enter any operator at runtime
Step 3: Enter any two integer values at runtime
Step 4: Apply switch case to select the operator:
//情况'+'：结果=num1+num2;
break;
case '-': result = num1 - num2;
break;
case '*': result = num1 * num2;
break;
case '/': result = num1 / num2;
break;
default: printf("\n Invalid Operator ");
Step 5: Print the result示例
以下是使用SwitchCase的计算器C程序-
#include <stdio.h>
int main(){
char Operator;
float num1, num2, result = 0;
printf("\n Enter any one operator like +, -, *, / : ");
scanf("%c", &Operator);
printf("Enter the values of Operands num1 and num2 \n : ");
scanf("%f%f", &num1, &num2);
switch(Operator){
case '+': result = num1 + num2;
break;
case '-': result = num1 - num2;
break;
case '*': result = num1 * num2;
break;
case '/': result = num1 / num2;
break;
default: printf("\n Invalid Operator ");
}
printf("The value = %f", result);
return 0;
}输出结果执行以上程序后，将产生以下结果-
Enter any one operator: + Enter values of Operands num1 and num2: 23 45 The value = 68.000000