C语言实现俄罗斯方块小游戏

2023-09-27 09:57:29 50

C语言实现俄罗斯方块小游戏的制作代码，具体内容如下

#include
#include
#include


#defineTTY_PATH"/dev/tty"
#defineSTTY_ON"sttyraw-echo-F"
#defineSTTY_OFF"stty-rawecho-F"

intmap[21][14];
chardirect;

intnode[7][4][16]={
{{0,0,0,0,1,1,1,1,0,0,0,0,0,0,0,0},//长方形
{0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,0},
{0,0,0,0,1,1,1,1,0,0,0,0,0,0,0,0},
{0,1,0,0,0,1,0,0,0,1,0,0,0,1,0,0}},
{{1,1,0,0,1,1,0,0,0,0,0,0,0,0,0,0},//正方形
{1,1,0,0,1,1,0,0,0,0,0,0,0,0,0,0},
{1,1,0,0,1,1,0,0,0,0,0,0,0,0,0,0},
{1,1,0,0,1,1,0,0,0,0,0,0,0,0,0,0}},
{{0,1,0,0,1,1,1,0,0,0,0,0,0,0,0,0},//3边加一中点
{0,1,0,0,0,1,1,0,0,1,0,0,0,0,0,0},
{0,0,0,0,1,1,1,0,0,1,0,0,0,0,0,0},
{0,1,0,0,1,1,0,0,0,1,0,0,0,0,0,0}},
{{0,1,1,0,0,1,0,0,0,1,0,0,0,0,0,0},//右锄头型
{0,0,0,0,1,1,1,0,0,0,1,0,0,0,0,0},
{0,1,0,0,0,1,0,0,1,1,0,0,0,0,0,0},
{1,0,0,0,1,1,1,0,0,0,0,0,0,0,0,0}},
{{1,1,0,0,0,1,0,0,0,1,0,0,0,0,0,0},//左锄头型
{0,0,1,0,1,1,1,0,0,0,0,0,0,0,0,0},
{0,1,0,0,0,1,0,0,0,1,1,0,0,0,0,0},
{0,0,0,0,1,1,1,0,1,0,0,0,0,0,0,0}},
{{0,1,0,0,0,1,1,0,0,0,1,0,0,0,0,0},//右曲折型
{0,1,1,0,1,1,0,0,0,0,0,0,0,0,0,0},
{0,1,0,0,0,1,1,0,0,0,1,0,0,0,0,0},
{0,1,1,0,1,1,0,0,0,0,0,0,0,0,0,0}},
{{0,1,0,0,1,1,0,0,1,0,0,0,0,0,0,0},//左曲折型
{1,1,0,0,0,1,1,0,0,0,0,0,0,0,0,0},
{0,1,0,0,1,1,0,0,1,0,0,0,0,0,0,0},
{1,1,0,0,0,1,1,0,0,0,0,0,0,0,0,0}}
};

typedefstructblock
{
intx;
inty;
intblockType;
intblockDirect;
}Block;
Blockbl;

voidinit_map()//初始化边框
{
inti,j;
for(i=0;i<21;i++)
for(j=0;j<14;j++)
{
if(j==0||j==13)
map[i][j]=200;
elseif(i==20)
map[i][j]=201;
else
map[i][j]=0;
}
}
voidnew_block()//生成随机的俄罗斯方块
{
intblockType=rand()%7;
intblockDirect=rand()%4;
intx=1;
inty=5;
bl.x=x;
bl.y=y;
bl.blockType=blockType;
bl.blockDirect=blockDirect;
}

voidinput()//将移动后的俄罗斯方块，导入地图中作标记
{
inti,j;
for(i=0;i<4;i++)
for(j=0;j<4;j++)
if(node[bl.blockType][bl.blockDirect][i*4+j]==1)
{
map[bl.x+i][bl.y+j]=1;
}
}
voidoutput()//移动时，将之前俄罗斯方块在地图信息清空。
{
inti,j;
for(i=0;i<4;i++)
for(j=0;j<4;j++)
if(node[bl.blockType][bl.blockDirect][i*4+j]==1)
{
map[bl.x+i][bl.y+j]=0;
}
}

voidchange()//俄罗斯方格在碰撞后融入，固定
{
inti,j;
for(i=0;i<4;i++)
for(j=0;j<4;j++)
if(node[bl.blockType][bl.blockDirect][i*4+j]==1)
{
map[bl.x+i][bl.y+j]=10;
}
for(j=1;j<13;j++)
if(map[5][j]==10)
{
system("clear");
printf("gameover!!!!!!!!!\n");
exit(1);
}
}


voidprint_map()//打印地图，显示信息
{
inti,j;
for(i=5;i<21;i++)
{
for(j=0;j<14;j++)
{
if(map[i][j]==200)//左右边界
printf("#");
elseif(map[i][j]==201)//下边界
printf("#");
elseif(map[i][j]==0)//空白地
printf("");
elseif(map[i][j]==1)//移动的俄罗斯方块
printf("*");
elseif(map[i][j]==10)//固定的俄罗斯方块
printf("@");
}
printf("\n");
}
}
voiddelLine(intn)//消行
{
inti,j;
for(j=1;j<13;j++)
map[n][j]=0;
for(i=n;i>5;i--)
for(j=1;j<13;j++)
if(map[i-1][j]!=1)
map[i][j]=map[i-1][j];
}

voidisFillLine()//是否满足消行条件
{

inti,j;
intfals;
for(i=19;i>5;i--)
{
fals=1;
for(j=1;j<13;j++)
{
if(map[i][j]!=10)
{
fals=0;
continue;
}
}
if(fals)
{
delLine(i);
}
}
}
voiddown()//下移
{
inti,j;
intfale=1;
for(i=3;i>=0;i--)
for(j=0;j<4;j++)
if(node[bl.blockType][bl.blockDirect][i*4+j]==1)
if(map[bl.x+i+1][bl.y+j]==10||map[bl.x+i+1][bl.y+j]==201)
{
change();
fale=0;
new_block();
isFillLine();
return;
}
if(fale)
{
output();
bl.x+=1;
input();
}

}
voidright()//右移
{
inti,j;
intfale=1;
for(i=3;i>=0;i--)
for(j=0;j<4;j++)
if(node[bl.blockType][bl.blockDirect][i*4+j]==1)
if(map[bl.x+i][bl.y+j+1]==10||map[bl.x+i][bl.y+j+1]==200)
{
fale=0;
return;
}
if(fale)
{
output();
bl.y+=1;
input();
}

}
voidleft()//左移
{
inti,j;
intfale=1;
for(i=3;i>=0;i--)
for(j=0;j<4;j++)
if(node[bl.blockType][bl.blockDirect][i*4+j]==1)
if(map[bl.x+i][bl.y+j-1]==10||map[bl.x+i][bl.y+j-1]==200)
{
fale=0;
return;
}
if(fale)
{
output();
bl.y-=1;
input();
}

}

voidchange_block()//俄罗斯方块变形
{
inti,j;
output();
intfals=1;
bl.blockDirect+=1;
bl.blockDirect%=4;
for(i=0;i<4;i++)
for(j=0;j<4;j++)
if(node[bl.blockType][bl.blockDirect][i*4+j]==1)
if(map[bl.x+i][bl.y+j]!=0)
{
fals=0;
break;
}
if(fals)
{
input();
}else
{
bl.blockDirect-=1;
input();
}
}

charin_direct()//非堵塞输入
{
fd_setfd;
structtimevaltv;
charch;
FD_ZERO(&fd);
FD_SET(0,&fd);
tv.tv_sec=0;
tv.tv_usec=10;
if(select(1,&fd,NULL,NULL,&tv)>0)
{
ch=getchar();
}
returnch;
}
intmain()//q退出游戏，a,d左右移动，空格变形
{
srand(time(NULL));
init_map();
new_block();
input();
charch;
intnum=0;
while(1)
{
usleep(500000);
system(STTY_ONTTY_PATH);
ch=in_direct();
system(STTY_OFFTTY_PATH);
system("clear");
if(ch=='a'&&num<=1)
{
left();
print_map();
num++;
continue;
}elseif(ch=='d'&&num<=1)
{
right();
print_map();
num++;
continue;
}elseif(ch==''&&num<=1)
{
change_block();
print_map();
num++;
continue;
}elseif(ch=='q')
{
system("clear");
printf("gaveover!!!!!\n");
exit(0);
}
down();
print_map();
num=0;

}
return0;
}

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