python入门之井字棋小游戏
引言:
刚学python好几天了,从java到python,基础学起来确实比较容易,语法掌握,基本概念上都比较容易入脑。
唯一比较郁闷的是老想着用java的语法去学python代码,这点还需要后面慢慢掌握吧,相信学多种语言的你们也有这种经历吧。
start:开始上代码了,希望有更好的逻辑思维来写,自己也是用最笨拙的思路去写的,如果有可以优化的代码请各位大神指教
#!/user/bin/python #-*-coding:utf-8-*- importos importsys #棋盘模块 defmodel(dictionary,serial=False): ifserial: print('-(初版)井字棋游戏,输入棋号进行对战,') print('对应棋号为第一行:a1-a2-a3',end=',') print('对应棋号为第二行:b1-b2-b3',end=',') print('对应棋号为第三行:c1-c2-c3') print(dictionary['a1']+'|'+dictionary['a2']+'|'+dictionary['a3']+'|') print('-+-+-+-') print(dictionary['b1']+'|'+dictionary['b2']+'|'+dictionary['b3']+'|') print('-+-+-+-') print(dictionary['c1']+'|'+dictionary['c2']+'|'+dictionary['c3']+'|') #主模块 defmain(): dictionary={'a1':'','a2':'','a3':'','b1':'','b2':'','b3':'','c1':'','c2':'','c3':''} model(dictionary,True) u1='x'#用户1 u2='o'#用户2 stepNumber=1#记录步数 break_fang=0#获胜者记录 while(stepNumber<=9): fv=True#判断条件2 whilefv: num=input('请用户u1开始下棋:') compare=1#判断条件1 forxindictionary: ifx.find(num)!=-1:compare=0 ifcompare==0: fv=False dictionary[num]=u1 model(dictionary) #0:继续1,用户1胜,2,用户2胜 break_fang=forResult(dictionary) ifbreak_fang>0:break fv=True#清楚状态 stepNumber+=1 whilefv: num1=input('请用户u2开始下棋:') compare=1#判断条件1 forxindictionary: ifx.find(num1)!=-1:compare=0 ifcompare==0: fv=False dictionary[num1]=u2 model(dictionary) break_fang=forResult(dictionary) ifbreak_fang>0:break stepNumber+=1 gameover(break_fang) #退出下棋 defgameover(break_fang): c=input('是否重新开始?yes:no:') ifc.find('yes')!=-1: main() else: print('-游戏结束-') return #判断获胜情况 #dictionary:棋盘信息 defforResult(dictionary): dicts=dict(dictionary) ifdicts['a1']==dicts['a2']anddicts['a2']==dicts['a3']andlen(dicts['a3'].strip())>0: print('游戏结束,'+'用户1-获胜'ifdicts['a1']=='x'else'用户2-获胜') return1ifdicts['a1']=='x'else2 elifdicts['a1']==dicts['b2']anddicts['b2']==dicts['c3']andlen(dicts['c3'].strip())>0: print('游戏结束,'+'用户1-获胜'ifdicts['a1']=='x'else'用户2-获胜') return1ifdicts['a1']=='x'else2 elifdicts['a1']==dicts['b1']anddicts['b1']==dicts['c1']andlen(dicts['c1'].strip())>0: print('游戏结束,'+'用户1-获胜'ifdicts['a1']=='x'else'用户2-获胜') return1ifdicts['a1']=='x'else2 elifdicts['a2']==dicts['b2']anddicts['b2']==dicts['c2']andlen(dicts['c2'].strip())>0: print('游戏结束,'+'用户1-获胜'ifdicts['a2']=='x'else'用户2-获胜') return1ifdicts['a2']=='x'else2 elifdicts['a3']==dicts['b3']anddicts['b3']==dicts['c3']andlen(dicts['c3'].strip())>0: print('游戏结束,'+'用户1-获胜'ifdicts['a3']=='x'else'用户2-获胜') return1ifdicts['a3']=='x'else2 elifdicts['a3']==dicts['b2']anddicts['b3']==dicts['c1']andlen(dicts['c1'].strip())>0: print('游戏结束,'+'用户1-获胜'ifdicts['a3']=='x'else'用户2-获胜') return1ifdicts['a3']=='x'else2 elifdicts['b1']==dicts['b2']anddicts['b2']==dicts['b3']andlen(dicts['b3'].strip())>0: print('游戏结束,'+'用户1-获胜'ifdicts['b1']=='x'else'用户2-获胜') return1ifdicts['b1']=='x'else2 elifdicts['c1']==dicts['c2']anddicts['c2']==dicts['c3']andlen(dicts['c3'].strip())>0: print('游戏结束,'+'用户1-获胜'ifdicts['c1']=='x'else'用户2-获胜') return1ifdicts['c1']=='x'else2 else: return0 if__name__=='__main__': main()
补一点更改思路:forResult()的另一种实现,compares()函数:少了6行代码量。
defcompares(dictionary={'':''},string=''): iflen(dictionary)>0|len(string.strip())==0:print('传值为空!') else: axle=('a1','a3','b2','c1','c3')#四个角和中间的数特殊判断条件1 axle_fang=False#特殊棋号需要多加一种可能性 forxinaxle: ifstring==x:axle_fang=True ifaxle_fang:#条件1 ifdictionary['a1']==dictionary['b2']anddictionary['b2']==dictionary['c3']anddictionary['c3'].strip()!=''\ ordictionary['a3']==dictionary['b2']anddictionary['b2']==dictionary['c1']anddictionary['c1'].strip()!='': print('游戏结束,'+'用户1-获胜'ifdictionary[string]=='x'else'用户2-获胜') return1ifdictionary[string]=='x'else2 #拆分棋号splitStr0,splitStr1,普通棋号只需判断俩种a俩种可能,上下-左右间的位置 splitStr0,splitStr1=string[0],string[1] print(splitStr0+":"+splitStr1) ifdictionary[splitStr0+'1']==dictionary[splitStr0+'2']anddictionary[splitStr0+'2']==dictionary[splitStr0+'3']\ ordictionary['a'+splitStr1]==dictionary['b'+splitStr1]anddictionary['b'+splitStr1]==dictionary['c'+splitStr1]: print('游戏结束,'+'用户1-获胜'ifdictionary[string]=='x'else'用户2-获胜') return1ifdictionary[string]=='x'else2 else:return0
end:写完这些也有九十行代码量了,总感觉太多了。
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