python实现mask矩阵示例(根据列表所给元素)
行和列的位置都在以下三个列表中的一列中,则对应位置为1,其余位置全为0
——[7-56,239-327,438-454,522-556,574-586]
——[57-85,96-112,221-238]
——[113-220,328-437,455-521,557-573]
代码实现
defgenerateMaskBasedOnDom(dom_path,length): """ :paramdom_path:thisisafilepath,whichcontainsthefollowinginformation: [7-56,239-327,438-454,522-556,574-586][57-85,96-112,221-238][113-220,328-437,455-521,557-573] each[...]meansonedomain :paramlength:thisisthelengthofthisprotein :return:themaskmatrixwithsizelengthxlength,1meansinnerdomainresiduepair,otherwise0 """ #读取文件 withopen(dom_path,"r",encoding="utf-8")asfile: contents=file.readlines() #获得mask位置数据 list0=[] list1=[] list2=[] forlist_idx,contentinenumerate(contents): num_range_list=content.strip()[1:-1].split(",") fornum_rangeinnum_range_list: start_num=int(num_range.split("-")[0]) end_num=int(num_range.split("-")[1]) fornuminrange(start_num,end_num+1): iflist_idx==0: list0.append(num) eliflist_idx==1: list1.append(num) else: list2.append(num) mask=np.zeros((length,length)) #遍历矩阵每个元素 forrowinrange(mask.shape[0]): forcolinrange(mask.shape[1]): if(rowinlist0andcolinlist0)or(rowinlist1andcolinlist1)or(rowinlist2andcolinlist2): mask[row][col]=1 returnmask if__name__=="__main__": #ifnodomfile,pleasegetdomfilefirst withopen("dom.txt","w",encoding="utf-8")asf: f.write("[7-56,239-327,438-454,522-556,574-586]"+"\n"+"[57-85,96-112,221-238]"+"\n"+"[113-220,328-437,455-521,557-573]") file_path="./dom.txt" protein_length=1000#mask_matrixsize mask_matrix=generateMaskBasedOnDom(file_path,protein_length) print("*************GenerateMaskMatrixSuccessful!*************") #随机测试几组 print(mask_matrix[7][56])#1 print(mask_matrix[7][239])#1 print(mask_matrix[8][57])#0 print(mask_matrix[57][95])#0 print(mask_matrix[113][573])#1
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