如何将结构的单个成员作为参数传递给 C 语言中的函数？
将单个成员作为参数传递给函数-
每个成员在函数调用中作为参数传递。
它们在函数头中的普通变量中独立收集。
示例
#include输出结果//Declaring structure// struct student{ int s1,s2,s3; }s[5]; //Declaring and returning Function// void addition(int a,int b,int c){ //Declaring sum variable and For loop variable// int i,sum; //Arithmetic Operation// for(i=1;i<4;i++){ sum=a+b+c; printf("Student %d scored total of %d\n",i,sum); } } void main(){ //Declaring variable for For loop// int i; //Reading User I/p through For loop// for(i=1;i<4;i++){ printf("Enter marks for student %d in subject 1 = ",i); scanf("%d",&s[i].s1); printf("Enter marks for student %d in subject 2 = ",i); scanf("%d",&s[i].s2); printf("Enter marks for student %d in subject 3 = ",i); scanf("%d",&s[i].s3); } //Calling function// addition(s[].s1,s[].s2,s[].s3); }
day = 2 month = 1 year = 2010