C程序计算两个时间段之间的差异!
输入带有小时、分钟和秒的开始和停止时间。最后，我们需要找到开始时间和停止时间之间的差异。
下面给出了找到开始时间和停止时间之间差异的逻辑-
while (stop.sec > start.sec){
--start.min;
start.sec += 60;
}
diff->sec =start.sec- stop.sec;
while (stop.min > start.min) {
--start.hrs;
start.min += 60;
}
diff->min =start.min- stop.min;
diff->hrs =start.hrs- stop.hrs;示例
以下是查找开始时间和停止时间之间差异的程序-
#include输出结果struct time { int sec; int min; int hrs; }; void diff_between_time(struct time t1, struct time t2, struct time *diff); int main(){ struct time start_time, stop_time, diff; printf("Enter start time. \n"); printf("Enter hours, minutes and seconds: "); scanf("%d %d %d", &start_time.hrs, &start_time.min, &start_time.sec); printf("Enter the stop time. \n"); printf("Enter hours, minutes and seconds: "); scanf("%d %d %d", &stop_time.hrs, &stop_time.min, &stop_time.sec); //开始时间和停止时间的区别 diff_between_time(start_time, stop_time, &diff); printf("\ntime Diff: %d:%d:%d - ", start_time.hrs, start_time.min, start_time.sec); printf("%d:%d:%d ", stop_time.hrs, stop_time.min, stop_time.sec); printf("= %d:%d:%d\n", diff.hrs, diff.min, diff.sec); return 0; } //计算时间段之间的差异 void diff_between_time(struct time start, struct time stop, struct time *diff){ while (stop.sec > start.sec) { --start.min; start.sec+= 60; } diff->sec =start.sec- stop.sec; while (stop.min > start.min) { --start.hrs; start.min+= 60; } diff->min =start.min- stop.min; diff->hrs =start.hrs- stop.hrs; }
执行上述程序时，会产生以下结果-
Enter start time. Enter hours, minutes and seconds: 12 45 57 Enter the stop time. Enter hours, minutes and seconds: 20 35 20 time Diff: 12:45:57 - 20:35:20 = -8:10:37