使用小于运算符创建盒子并计算体积和检查的 C++ 程序
假设我们必须定义一个条件很少的盒子类。这些如下-
长度、宽度和高度分别有l、b和h三个属性，（这些是私有变量）
定义一个非参数化构造函数以将l、b、h设置为0，并定义一个参数化构造函数以初始设置值。
为每个属性定义getter方法
定义一个函数calculateVolume()获取盒子的体积
重载小于运算符(<)以检查当前框是否小于另一个框。
创建一个可以计算创建的框数的变量。
所以，如果我们输入三个框(0,0,0)(5,8,3),(6,3,8)并显示每个框的数据，并检查第三个框是否小于第二个，以及找到较小盒子的体积，并通过计数变量打印它们有多少个盒子。
然后输出将是
Box 1: (length = 0, breadth = 0, width = 0) Box 2: (length = 5, breadth = 8, width = 3) Box 3: (length = 6, breadth = 3, width = 8) Box 3 is smaller, its volume: 120 共有 3 box(es)
示例
让我们看看以下实现以获得更好的理解-
#includeusing namespace std; class Box { int l, b, h; public: static int count; Box() : l(0), b(0), h(0) { count++; } Box(int length, int breadth, int height) : l(length), b(breadth), h(height) { count++; } int getLength() const {return l;} int getBreadth() const {return b;} int getHeight() const {return h;} long long CalculateVolume() const { return 1LL * l * b * h; } bool operator<(const Box& another) const { if (l != another.l) { return l < another.l; } if (b != another.b) { return b < another.b; } return h < another.h; } }; int Box::count = 0; int main(){ Box b1; Box b2(5,8,3); Box b3(6,3,8); printf("Box 1: (length = %d, breadth = %d, width = %d)\n",b1.getLength(), b1.getBreadth(), b1.getHeight()); printf("Box 2: (length = %d, breadth = %d, width = %d)\n",b2.getLength(), b2.getBreadth(), b2.getHeight()); printf("Box 3: (length = %d, breadth = %d, width = %d)\n",b3.getLength(), b3.getBreadth(), b3.getHeight()); if(b3 < b2){ cout << "Box 3 is smaller, its volume: " << b3.CalculateVolume() << endl; }else{ cout << "Box 3 is smaller, its volume: " << b2.CalculateVolume() << endl; } cout << "共有 " << Box::count << " box(es)"; }
输入
b1; b2(5,8,3); b3(6,3,8);输出结果
Box 1: (length = 0, breadth = 0, width = 0) Box 2: (length = 5, breadth = 8, width = 3) Box 3: (length = 6, breadth = 3, width = 8) Box 3 is smaller, its volume: 120 共有 3 box(es)